Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6679241
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T04:20:12+00:00 2026-05-26T04:20:12+00:00

I have 2 pages : page1.php : – has a form with text box

  • 0

I have 2 pages :

page1.php :
– has a form with text box and a “submit” button. Eg : <form name="frm_register" action="page1.php" method="post">

– php and mysql code to store the value of textbox to database. Javascript will redirect the page to php2.php after the value is submitted to database. Eg :

$query = "INSERT INTO traceuser (username) VALUES ('{$username}')";
$result = mysql_query($query, $connection);
echo '<script language="javascript">window.location="page2.php";</script>';

page2.php
– mysql retrieve the data from database and display on this page.

Problem : When I press “back” button, the browser will pop up a warning message saying that the form will be resubmit. How to prevent resubmit the form when click “back” button? Is it I need to clear the cache of page1.php? How to do it with php or javascript or ajax?


Update 1 : Thanks for the answer of replacing javascript window.location="page2.php" to php header('Location: home2.php');. It fix 80% of problem. The rest of 20% problem show below :

    if (strtotime($_SESSION['servertime']) < time()-3){ //10800 = 3 hours 3600 = 1 hour
                if (($username != "") AND ($username != $_SESSION[username])){
                    $_SESSION['servertime'] = $servertime; 
                    $_SESSION['username'] = $username;
                    $query = "INSERT INTO traceuser (username) VALUES ('{$username}')";
                    $result = mysql_query($query20, $connection);
                    header('Location: page2.php');
                    exit;
                } else {
                    echo "same name"; //problem here
                }
            }else{
                echo "submit multiple data too fast"; //problem here too.
            }
   }

The problem happen when do the following steps :
1) User submit data successfully, jump to page2.php view records.
2) User click “back” button, jump back to page1.php.
3) User submit data fail, stay on page1.php. (because too fast or same name)
4) User submit data successful, jump to page2.php view records.
5) User click “back” button, but browser shows warning message “form will be resubmited”.

The problem is because of Step 3. Step 3 didn’t run header('Location: page2.php');, didn’t jump to page2.php. So it cause Step 5 show the warning message. How to fix this problem?


Update 2 : I have figured out the solution to fix the 20% problem, it works perfectly. I use session['error123'] to decide whether or not want to display the error message “same name”. I kill session['error123'] if success submit data to database or if success jump to page2.php. I also use header('Location: page1.php'); to redirect to own page (same page) to make the page forget about form submission previously. Example of codes :

if ($_SESSION['error123'] == "toofast"){
    echo $_SESSION['error123'] ;
}elseif ($_SESSION['error123'] == "samename"){
    echo $_SESSION['error123'] ;
}

if (strtotime($_SESSION['servertime']) < time()-3){ //10800 = 3 hours 3600 = 1 hour
                if (($username != "") AND ($username != $_SESSION['username'])){
                    $_SESSION['username'] = $username;
                    $query = "INSERT INTO traceuser (username) VALUES ('{$username}')";
                    $result = mysql_query($query20, $connection);
                    $_SESSION['error123'] = "aa";
                    header('Location: http://localhost/plekz/page2.php');
                    exit;
                } else {
                    $_SESSION['error123'] = "samename";
                    header('Location: http://localhost/plekz/page1.php');
                    exit;
                }
            }else{
                $_SESSION['error123'] = "toofast";
                header('Location: http://localhost/plekz/page1.php');
                    exit;
            }
        }
    }

Note : You need to buffer the output by <?php ob_start();?> because $_SESSION cannot put before header(). Buffer will stop all output including session, let header() send the output first.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T04:20:13+00:00Added an answer on May 26, 2026 at 4:20 am

    Rather than

    echo '<script language="javascript">window.location="page2.php";</script>';

    you should use the header() function to redirect your user after the submission.

    So in psuedo code,

    click submit on page.php action page1.php
    page1.php submits data to database calls

    header('Location: http://example.com/page2.php');
    

    This should prevent your clicking back problem

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have page1.php that uses a form to send the following data: <form action=page2.php
I have the following pages: page1.php <?php if (isset($_GET['link'])) { session_start(); $_session['myvariable'] = 'Hello
I have the following pages: page1.php, page2.php and page3.php. Code in each of them
Suppose i have one website with simple pages in php like page1.php page2.php Now
I have a page (page1.php) where I am using a select box to load
I have many sub pages, there urls like www.domain.com/sub/page1.php www.domain.com/sub/page2.php ... Now when I
HI, i have 2 php pages.first page has some functions like Connect(),... .i want
I have pages like this: page.php?id=1&name=whatever How could I transform this into... page/1/whatever
On my website I have created my pages like so: http://www.website.com/page1.php http://www.website.com/page2.php http://www.website.com/page3.php This
If I have $var defined in Page1.php and in Page2.php I have //Page2.php include('Page1.php');

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.