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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T07:50:55+00:00 2026-06-12T07:50:55+00:00

I have 2 separate forms. The first form handler determines if the second form

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I have 2 separate forms. The first form handler determines if the second form is needed. Each form populates a separate database table. I need to be able to link corresponding rows later. I am trying to do so by calling SCOPE_IDENTITY() after the first form and setting it to a variable to be used as the id in the second form.

I hope that made sense. Here’s my code:

 $iquery = mysql_query("INSERT INTO pending (date, ip) VALUES('".$_POST['date']."', '".$_POST['ip']."')");
$asdf = SCOPE_IDENTITY();
echo $asdf;

Which give gives me this:

Fatal error: Call to undefined function scope_identity() in
/public_html/test/index.php on line 138

What is the correct way to do this? keep in mind I need the result to be set as a variable.

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  1. Editorial Team
    Editorial Team
    2026-06-12T07:50:56+00:00Added an answer on June 12, 2026 at 7:50 am

    Use mysql_insert_id():

    $asdf = mysql_insert_id();
    

    or in PDO (which I’m advising you to move, here is a nice tutorial):

    $asdf = $db->lastInsertId();
    
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