Question

I have 2 seperate select statements, using aggregate functions in each. I would like to be able to take the results and combine them.

table_a
id int
entered_date datetime (holds utc stamp)
balance money
group_id int

table_b
id int
entered_date date
balance money
transaction_type int

query 1: 
select convert(date,entered_date), sum(balance) as earned
from table_a
where group_id in (1, 2, 3, 4)
group by convert(date,entered_Date)

query 2: 
select convert(date,entered_date), sum(balance) as spent
where transaction_type = 2
group by convert(date,entered_Date)

results:
query 1:
2012-05-13, 5000
2012-05-14, 12000
...

query 2:
2012-05-13, 9000
2012-05-14, 55856
...

I would like to return one row for each record without using temp tables. The result set should have a date, then earned vs. spent. I have a report running using union to get the totals and that is fine, but i need to generate a result set with 1 record and a earned vs against line. Any help with this is appreciated.

Answer 1

Try:

;With AllDates AS
(
select convert(date,entered_date) As EnteredDate
    from table_a
    where group_id in (1, 2, 3, 4)
    group by convert(date,entered_Date)
UNION
select convert(date,entered_date)
    from table_b
    where transaction_type = 2
    group by convert(date,entered_Date)
)
, AllEarned AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Earned
    from table_a
    where group_id in (1, 2, 3, 4)
    group by convert(date,entered_Date)
)
, AllSpent AS (
select convert(date,entered_date) AS EnteredDate, sum(balance) as Spent
    from table_b
    where transaction_type = 2
    group by convert(date,entered_Date)
)
SELECT
    d.EnteredDate, e.Earned, s.Spent
    FROM AllDates d
    LEFT OUTER JOIN AllEarned e ON d.EnteredDate=e.EnteredDate
    LEFT OUTER JOIN AllSpent s ON d.EnteredDate=s.EnteredDate
    ORDER BY 1,2,3