Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6985957
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T18:44:50+00:00 2026-05-27T18:44:50+00:00

i have 2 tables customer customerid customername orders customerid orderid isopen [true/false] How can

  • 0

i have 2 tables

customer

customerid    
customername

orders

customerid
orderid
isopen [true/false]

How can i create a view that will contain the following :

customer name , total orders , total orders where isopen column ==true

*Update**

create view CustomerOrders as
select c.id CustomerID, 
       max(c.customername) CustomerName,
       count(o.order_id) CustomerOrders,
       SUM(CASE WHEN o.isopen = 1 THEN 1 ELSE 0 END) AS OpenOrders
from customer c
left join orders o on c.id = o.customerid
group by c.id

Thank you all
mark please correct your answer so i can mark you

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T18:44:51+00:00Added an answer on May 27, 2026 at 6:44 pm

    Try:

    create view CustomerOrders as
    select c.customerid CustomerID, 
           max(c.customername) CustomerName,
           count(o.order_id) CustomerOrders,
           SUM(CASE WHEN o.isopen = 1 THEN 1 ELSE 0 END) OpenOrders
    from customer c
    left join orders o on c.customerid = o.customerid
    group by c.id
    

    (Assumes that you want to include customers with no orders – change the left join to an inner join if you want to include only customers with orders.)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Say I have 2 tables: Customers and Orders. A Customer can have many Orders.
I have 2 tables, that look like: CustomerInfo(CustomterID, CustomerName) CustomerReviews(ReviewID, CustomerID, Review, Score) I
I have four tables: Customer, CustomerCategory, Limit, and LimitCategory. A customer can be in
I have 3 tables. cinema, booking and customer create table cinema ( c_id int,
I have two tables as follows: CREATE TABLE customer ( id INT NOT NULL
I have to create a view to show an overview of orders in my
I have 2 tables Customer Order 2 Classes Customer Id-Name Order Id-Description. CustomerName My
I have these tables: customer -------- customer_id int name varchar(255) order ----- order_id int
I have two tables Group and Customer and of course two entities Group and
I have the following two tables: Customer { int Id int Name } Bills

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.