Question

I have 2 tables, the unique id’s in each table are the same in both tables.
How do I go about joining the data from both tables together in php?

When I normally pull data I do it like this:

    $get_board_array = mysql_query("SELECT * FROM posts WHERE user_id_to = '$id' ");
      while($posts = mysql_fetch_array($get_board_array))
        {
          $post_id = $get_post['post_id']; 
          $html_output .= "<p>".$post_id."</p>";
        }

As for pulling the data from separate tables and not getting it all mixed up, I was thinking of doing something like this:

$get_arrayA = mysql_query("SELECT * FROM tableA WHERE age = '36' ");
  while($dataA = mysql_fetch_array($get_arrayA))
  {

      $dataA_id = $dataA['id'];
      $dataA_firstName = $dataA['FirstName'];

  foreach($dataA_id)
    {
      $get_arrayB = mysql_query("SELECT * FROM tableB where id='".$dataA_id."'");
      while($dataB = mysql_fetch_array($get_arrayB))
      {

      $dataB_lastName = $dataB['LastName'];

      $html_output .= "<p>".$dataA_firstName.$dataB_lastName"</p>";

      echo $html_output;
      }
   }
}

Or would this be just too weird of a thing?

I know how to do it within SQL using inner join but how do I do something like that in PHP and output html?

Answer 1

It is because of you misguide use of wildcard (*) characters. STOP THAT !! This is what happens when arrogant php developers imagine that they do not need to learn SQL. If you need something , then select it.

SELECT 
    foo.foo_id, 
    foo.data as paramX , 
    bar.type,
    bar.something_else
FROM foo
    INNER JOIN bar USING (foo_id)
WHERE
    foo.state = 'open'
AND bar.type = 3