Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8666283
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T17:41:24+00:00 2026-06-12T17:41:24+00:00

I have 2 tables: usStateCities: And usstatescentroids: SELECT state,COUNT(*) AS count FROM usStateCities GROUP

  • 0

I have 2 tables:

usStateCities:
usStateCities

And usstatescentroids:
usstatescentroids

SELECT state,COUNT(*) AS  count  FROM usStateCities  GROUP BY state

Gives the number of cities in each state

SELECT *
FROM (SELECT state, COUNT(*)  AS count FROM  usstatecities ) AS a,
usstatescentroids b
WHERE a.state = b.state
GROUP BY state

Only gives one state and total number of cities in US
I want to find the number of cities in each state and the coordinates (lon,lat) of the centroid of each state.

CORRECTION I have change State to state. I cut and pasted older statements.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T17:41:26+00:00Added an answer on June 12, 2026 at 5:41 pm
    SELECT a.state, a.count, b.lon, b.lat 
    FROM (SELECT State, COUNT(*) AS count FROM usStateCities GROUP BY State) a
    LEFT JOIN usstatescentroids b ON b.state = a.State
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have tables like this: from sqlalchemy import Column, Integer, select from sqlalchemy.ext.declarative import
I have tables with listings, categories and one that maps them to each other.
Our client's request is to have tables in PDF with rounded corner. I only
I have tables like this COUNT tbl id, userid, linkid, count 4 1 6
I have tables of data samples, with a timestamp and some data. Each table
I have tables Houses, Companies, Streets, HouseTypes and associated Models. Each House belong to
I have tables Building and Address , where each Building is associated with 0..n
The dataset have tables and columns details got from the XML file.I want to
We have tables Site and Content in our database. Each site is operated by
I have tables A and B with identity PKs ida and idb : ex

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.