Question

I have 2 tables with this configuration:

table language('id', 'language_name', 'iso_code')
table translation('id', 'language_id', 'translated_text')

In the first table I have records:

---------------------------------
| id | language_name | iso_code |
---------------------------------
| 1  | English       | en       |
| 2  | Espanõl       | es       |
| 3  | Français      | fr       |
---------------------------------

The second table:

--------------------------------------
| id | language_id | translated_text |
--------------------------------------
| 1  | 1           | Good Morning    |
| 2  | 1           | How are you?    |
| 1  | 2           | Buenos dias     |
| 2  | 3           | Comment ça va?  |
--------------------------------------

All English text strings exist, but some of the other languages dont.

I would like to show a table with ALL English text strings and corresponding translations, like:

----------------------------------------
| text_id | en           | es          |
----------------------------------------
| 1       | Good Morning | Buenos dias |
| 2       | How are you? |             |
----------------------------------------

or

-------------------------------------------
| text_id | en           | fr             |
-------------------------------------------
| 1       | Good Morning | Comment ça va? |
| 2       | How are you? |                |
-------------------------------------------

Any ideas?

Answer 1

Just keep doing left joins to same table on the ID, but extra columns representing their language…

Edited to show English if no value in corresponding columns per comment inquiry.

select 
      eng.id,
      eng.translated_text InEnglish,
      coalesce( spn.translated_text, eng.translated_text ) InSpanish,
      coalesce( frn.translated_text, eng.translated_text )  InFrench
   from
      translation eng
         left join translation spn
            on eng.id = spn.id
            and spn.Language_ID = 2
         left join translation frn
            on eng.id = frn.id
            and spn.Language_ID = 3
   where
      eng.Language_id = 1
   order by 
      eng.id