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Home/ Questions/Q 8813437
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T03:51:04+00:00 2026-06-14T03:51:04+00:00

I have 2D numpy array, with example shape: >>> a.shape (48, 160) and I

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I have 2D numpy array, with example shape:

>>> a.shape
(48, 160)

and I want to do simple operation between elements or each row, like a[0] - a[1] but for every row against all other rows.

I know how to do it simply by using for loop and iterating rows, but I was wondering if there is some numpy slicing specific instruction, that can do this without using for loops

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  1. Editorial Team
    Editorial Team
    2026-06-14T03:51:05+00:00Added an answer on June 14, 2026 at 3:51 am

    You can use broadcasting magic to do this.

    import numpy as np
    a = np.arange(12).reshape((4, 3))
    b = np.arange(15).reshape((5, 3))
    diff = a[np.newaxis, :, :] - b[:, np.newaxis, :]
    diff.shape
    # (5, 4, 3)
    

    This is a good broadcasting tutorial. In this case I make a (1, 4, 3) and b (5, 1, 3) and I get a result that’s (5, 4, 3), the difference of every row pair in a and b.

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