Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 678993
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T01:12:39+00:00 2026-05-14T01:12:39+00:00

i have 3 tables A,B and C. table A has column employee_name,id table B

  • 0

i have 3 tables A,B and C.

  • table A has column employee_name,id
  • table B is the main table and has columns id,os version.
  • table c has the columns id,package id and p_version.

I want to query the count of employee_name where the id of table a and c are matched with id of table b(which is the main table).

I should also get the names of employees grouped by the os version they have and also the p_version.

i have tried,

select count(employee_name),os.version,p_version where a.id=b.id and b.id=c.id;

i want the count of employee names to be grouped by os.version and p_version.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T01:12:40+00:00Added an answer on May 14, 2026 at 1:12 am

    I’m not too certain I understand your requirements .. the following is a blind guess.

    I’m not too certain how table c should be connected to table b, btw .. somehow the schema doesn’t make alot of sense to me!

    select  b.os
         , c.package_version
         , count(a.employee_name)
    from B
      join A  on (b.id=a.id)
      join C  on (b.id=c.id)
    group by b.os,c.package_version
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a table where one column has duplicate records but other columns are
My question is: I have two tables: table A has two columns (KeyA and
I have 2 tables- master and detail table. Master Table has ID column which
I have a table that has a column that has the cost of a
i have a table that has following column Type -------- type 1 type 2
I have mysql table that has a column that stores xml as a string.
I have a table which has a column called Direct of type char(1). It's
I have two tables one has a three column composite key. The other needs
Here's the caveat... If you have a table that has a single column and
I have a table that has a processed_timestamp column -- if a record has

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.