Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4068690
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T16:24:23+00:00 2026-05-20T16:24:23+00:00

I have 3 tables Tag, Software and Software_Tag which make many-to-many relationship between two

  • 0

I have 3 tables Tag, Software and Software_Tag which make many-to-many relationship between two first.

I wish to split the subquery out on two parts (because i can not do in in one in mysql):


(SELECT softwares_id FROM Software_Tag GROUP BY softwares_id HAVING COUNT(*) >=2) as my

DELETE FROM Software_Tag WHERE tags_id=1 AND softwares_id IN (my)

Here i try use virtual table named ‘my’ to put it to second query.
How could i do it?

now it gets en exception like check your sql server.

—

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T16:24:24+00:00Added an answer on May 20, 2026 at 4:24 pm

    You could just do it as:

    DELETE FROM Software_Tag WHERE tags_id=1 AND softwares_id IN
    (SELECT softwares_id FROM Software_Tag GROUP BY softwares_id HAVING COUNT(*) >=2)
    

    This should work in MySQL.

    Edit .. try this

    DELETE ST1
    FROM Software_Tag ST1 
    JOIN (SELECT softwares_id FROM Software_Tag GROUP BY softwares_id HAVING COUNT(*) >=2) ST2 on ST1.softwares_id=ST2.softwares_id
    where ST1.tags_id=1
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have two tables books and tags which are in a many-to-many relationship via
So essentially I have two tables, containing URLS and TAGS, with a has-and-belongs-to-many relationship
I have two tables: photos (id,path) and tags(id,name) . Tables are in many-to-many relationship,
I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255)
I have two related tables in my database: Page and Tag. One Page can
I have two tables which looks like this: News: (ID, Title, TagID) Tags: (ID,
I have two tables, one is a table of names with a category tag
I have software<-m:n->tag where software is main part of the relationship (tag has mappedby=softwares
We have two tables resembling a simple tag-record structure as follows (in reality it's
I have two tables that are related, which, for the purpose of this question,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.