Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6137701
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T17:45:36+00:00 2026-05-23T17:45:36+00:00

I have 3 variable $day , $month and $year and I want to create

  • 0

I have 3 variable $day , $month and $year and I want to create a date variable with these 3 variables in this fromat : yyyy-mm-dd in php.

$year variable is a persian year for example $year= 1390

this code works properly but not for persian date :

date("d-m-Y", mktime(0, 0, 0, $fMonth, $fDay, $fYear));

How I can do it ?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T17:45:36+00:00Added an answer on May 23, 2026 at 5:45 pm

    So you’d want something like this:

    date("d-M-Y", mktime(0, 0, 0, $month, $day, $year));
    

    EDIT: Oops, sorry, fixed.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a day, month and year in php variables. How can I use
I have 3 variables $day, $month, $year each of them have the values what
I'm creating a date class in c++, which holds day, month and year variables
I have the following Nant Script snippet. <zip zipfile=${devEnvironment}..\dev-${datetime::get-year(datetime::now())}${datetime::get-month(datetime::now())}${datetime::get-day(datetime::now())}.zip> <fileset basedir=${devEnvironment}> <include name=**/*/> </fileset>
I have an asp.net mvc application with a route similar to: routes.MapRoute(Blog, {controller}/{action}/{year}/{month}/{day}/{friendlyName}, new
I have a birth_date variable in the Date format. I want to compare it
Let's say I have 3 variables like this: var Month = 8; // in
Say I have the following code: struct date { int day; int month; int
I have variable @count of datatype int.I am setting values to this @count. I
I have a variable that contains a 4 byte, network-order IPv4 address (this was

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.