Question

I have 4 jQuery objects (i.e. things constructed via $('ObjectID')), and I would like to perform the same operation to all of them, in an elegant fashion. I would have thought that something like these would work, but it doesn’t seem to:

$([obj1, obj2, obj3, obj4]).change(function() { otherObj.show(); }); $([obj1, obj2, obj3, obj4]).attr('disabled', 'disabled'); 

Is there a good syntax for this? It seems like a somewhat blinding oversight. Currently the best I’m seeing is

$([obj1, obj2, obj3, obj4]).each(     function() { this.change(function() { otherObj.show(); })); 

Answer 1

You mean you have:

var obj1 = $('...'); var obj2 = $('...'); var obj3 = $('...'); var obj4 = $('...'); 

?

If so, you can turn them into a single set:

var complete = obj1.add(obj2).add(obj3).add(obj4); 

and then just use the final set to:

complete.change(function() {   otherObj.show(); }).attr('disabled', true);