Question

I have 5 fields in my DB:

test1 = 1, test2 = 1, test3 = NULL, test4 = NULL, test5 = NULL

PHP code:

if(isset($result['test1'])){$test1= "Test1"; echo $test1};

if(isset($result['test2'])){$test2= "Test2"; echo $test2};

if(isset($result['test3'])){$test3= "Test3"; echo $test3};

if(isset($result['test4'])){$test4= "Test4"; echo $test4};

if(isset($result['test5'])){$test5= "Test5"; echo $test5};

$total = implode(", ", array_filter(array($test1, $test2, $test3, $test4, $test5)));

echo $total;

Finaly Output:

Undefined Variable test3 in Line 7

Undefined Variable test4 in Line 7

Undefined Variable test5 in Line 7

Test1, Test2

I came up with 3 possible ways to hopefully run the code with NULL values to see if I will get a blank page with no error, unfortunately, they all gave me “Underfined Variable” error:

1. if(isset($result['test3'])){$test3= "OK"; echo $test3};

2. if(!empty($result['test3'])){$test3= "OK"; echo $test3};

3. if($result['test3']=='1'){$test3= "OK"; echo $test3};

Help? Thanks in Advance!

Answer 1

if(isset($result['test1'])){$test1= "Test1"; echo $test1} else { $test1="Abrakadabra"; }