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Editorial Team
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Asked: 2026-05-16T13:59:31+00:00

i have 500 records in a table. one column holds all html data. so

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i have 500 records in a table. one column holds all html data. so e.g –
html> body> … /body> /html>.
What i want to do is a find and replace. i have this tag in every single record –
<table id="something something" />
i want to replace that in all the rows with <table id="" />
now the difficult part is all the “something something” is different for each and every alt.
So the only common tag is “table id=”. how can do a find an replace here?

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1 Answer

  1. Editorial Team

    Try this (assumes only one “table id” occurs in each):

    declare @TestTable table (
    html_data varchar(100)
)

insert into @TestTable
    (html_data)
    select '<html><body><table id="something something" /></body></html>'
    union all
    select '<html><body><table id="something different" /></body></html>'

select html_data from @TestTable

update t
    set html_data = LEFT(t.html_data, CHARINDEX('<table id="', t.html_data)-1) 
                    + '<table id="" />'
                    + RIGHT(t.html_data, LEN(t.html_data) - CHARINDEX(' />', t.html_data, CHARINDEX('<table id="', t.html_data)) - 2)
        from @TestTable t

select html_data from @TestTable

    EDIT: Based on feedback in the comments below, this modified code should work.

    declare @TestTable table (
    html_data varchar(100)
)

insert into @TestTable
    (html_data)
    select '<html><body><table id="xxx"><tr><td></td></tr></table>... </body></html>'

select html_data from @TestTable

update t
    set html_data = LEFT(t.html_data, CHARINDEX('<table id="', t.html_data)-1) 
                    + '<table id="">'
                    + right(t.html_data, LEN(t.html_data) - CHARINDEX('>', t.html_data, CHARINDEX('<table id="', t.html_data)))
        from @TestTable t

select html_data from @TestTable
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