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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T12:56:10+00:00 2026-05-15T12:56:10+00:00

I have 7 8-bit integer values per record that I want to store in

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I have 7 8-bit integer values per record that I want to store in Postgres. Pg doesn’t offer a single byte integer type, SMALLINT, or 2 bytes, being the smallest integer datatype. Is there anyway I can store my 7 8-bit numbers and save on space?

Would an array type with a 7 element array be more compact? Or, should I make a binary representation of my 7 numbers (for example, using pack in Perl) and store that in a single bytea field?

Any other suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-15T12:56:11+00:00Added an answer on May 15, 2026 at 12:56 pm

    Given that the overhead for any row in PostgreSQL is 23 bytes (HeapTupleHeaderData), if you really care about small amounts of space this much you’ve probably picked the wrong way to store your data.

    Regardless, since all the more complicated types have their own overhead (bytea adds four bytes of overhead for example, bit strings 5 to 8), the only way to accomplish what you’re looking for is to use a bigint (8 bytes), numerically shifting each value and OR-ing together the result. You can do this using the bit string operations to make the code easier–compute as bit string, then cast to bigint before storing–or just manually multiply/add if you want speed to be better. For example, here’s how you store two bytes together into a two byte structure and then get them back again:

    int2 = 256 * byte1 + byte2
    byte1 = int2 / 256
    byte2 = int2 % 256
    

    You can extend the same idea into storing 7 of them that way. Retrieval overhead is still going to be terrible, but you will have actually saved some space in the process. But not very much relative to just the row header.

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