Question

I have

@a = (1,2,3); print (@a ~~ (1,2,3))

and

@a = (1,2,3); print (@a == (1,2,3))

The first one is the one I expect to work, but it does not print anything. The second one does print 1.

Why? Isn’t the smart matching operator ~~ supposed to match in the case of @a ~~ (1,2,3)?

Answer 1

For a second, lets consider the slightly different

\@a ~~ (1,2,3)

~~ evaluates its arguments in scalar context, so the above is the same as

scalar(\@a) ~~ scalar(1,2,3)

• \@a (in any context) returns a reference to @a.
• 1, 2, 3 in scalar context is similar to do { 1; 2; 3 }, returning 3.

So minus a couple of warnings*, the above is equivalent to

\@a ~~ 3

What you actually want is

\@a ~~ do { my @temp = (1,2,3); \@temp }

which can be shortened to

\@a ~~ [ 1,2,3 ]

Finally, the magic of ~~ allows \@a to be written as @a, so that can be shortened further to

@a ~~ [ 1,2,3 ]

* — Always use use strict; use warnings;!