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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T16:02:27+00:00 2026-06-09T16:02:27+00:00

I have a 16GB CSV that is ;-seperated and the fields are always quoted.

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I have a 16GB CSV that is ;-seperated and the fields are always quoted. I need to quickly filter out rows where the second field is blank.

"12345";"987";"..." # keep it
"67890";"";"..."    # omit it

The first two fields are numbers only, if that matters for performance.

I figure, that awk might be the most performant tool for this but I can’t seem to get it right. I tried this, but it omits most lines wrongly:

cat huge.csv | awk '/^"\d+";"\d/' > filtered.csv

Of course it doesn’t have to be awk; any command line tool commonly found on linux and OS X will do.

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  1. Editorial Team
    Editorial Team
    2026-06-09T16:02:29+00:00Added an answer on June 9, 2026 at 4:02 pm

    Another solution simply using

    awk -F\" '$4' 
    

    i.e., your command would be:

    awk -F\" '$4' huge.csv > filtered.csv
    

    This sets the input field separator to " and checks the 4th field. If it’s non-zero it prints the line implicitly. Gives:

    "12345";"987";"..." # keep it
    

    tested with GNU awk 3.1.6

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