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Home/ Questions/Q 9005423
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T01:08:27+00:00 2026-06-16T01:08:27+00:00

i have a 2D array of string it is like: gsdfsdf | awfdsf asdasd

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i have a 2D array of string it is like:

gsdfsdf | awfdsf 
asdasd  | sjd    
çsadsfd | kdjfkj 
bsdmfbs | skfjef 
ıfjdhsb | döjfn  
zewkjf  | skjfkj 
iadsa   | dfjdkj 

i want to sort it according to first column as you see it has local(Turkish) characters, and after sorting it must be like:

asdasd  | sjd    
bsdmfbs | skfjef 
çsadsfd | kdjfkj 
gsdfsdf | awfdsf 
ıfjdhsb | döjfn  
iadsa   | dfjdkj 
zewkjf  | skjfkj 

any idea, tutorial or advice?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T01:08:28+00:00Added an answer on June 16, 2026 at 1:08 am

    Comparator should be improved for null checking,.. etc. but this should work!

    final String alphabet = "0123456789AaBbCcÇçDdEeFfGgĞğHhIıİiJjKkLlMmNnOoÖöPpQqRrSsŞşTtUuÜüVvWwXxYyZz";
    SortedMap<String,String> map = new TreeMap(new Comparator<String>() {
    
            @Override
            public int compare(String o1, String o2) {
                int n = Math.min(o1.length(), o2.length());
                int i=0;
                while((i < n) && (o1.charAt(i) == o2.charAt(i))){
                    i++;
                }
                if(i==n){
                    return 0;
                }
                if(alphabet.indexOf(o1.charAt(i)) < alphabet.indexOf(o2.charAt(i))){
                    return -1;
                }
                return 1;
            }
        });
    
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