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Home/ Questions/Q 8444151
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T09:19:54+00:00 2026-06-10T09:19:54+00:00

I have a 2d character array of the form arr[][] . I need to

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I have a 2d character array of the form arr[][]. I need to add a single character to the end and sometimes to the beginning of the ith or jth row in this array. Here is the code snippet:

 arr[j] = strcat(arr[j],")");
 arr[i] = strcat("(",arr[i]);

When I compile the code, I get the error: incompatible types in assignment. Now I am assuming arr[j] and arr[i] are strings. Where am I going wrong? In other words, what is the best practice to append or add a character to the beginning of a string?

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  1. Editorial Team
    Editorial Team
    2026-06-10T09:19:56+00:00Added an answer on June 10, 2026 at 9:19 am

    First of all, you cannot assign the char * returned by strcat to an existing array row.

    But more importantly, strcat does not allocate a new string with the result of the concatenation, but instead performs the concatenation inplace in the first string. The return value is always the first string and is just a convenience. So, in the first case you just have to do:

    strcat(arr[j],")");
    

    (assuming arr[j] is big enough for the added character)

    The second case is more complicated, since you have to add the ) to the beginning of an existing string. You can e.g. perform the operation in a separated buffer and then copy it back to arr[j] using strcpy, or move the whole content of the string one character forward and add the parenthesis manually:

    memmove(arr[j]+1, arr[j], strlen(arr[j]));
    arr[j][0]='(';
    

    From your mistake I fear you think that char * is like the string classes in other languages, but alas it’s not like that. Remember, in C strings are just dumb arrays of characters, don’t expect any fancy commodities as in higher-level languages.

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