Question

I have a 3×3 array that I’m trying to create a pointer to and I keep getting this array, what gives?

How do I have to define the pointer? I’ve tried every combination of [] and *.

Is it possible to do this?

int tempSec[3][3];

int* pTemp = tempSec;

Answer 1

You can do int *pTemp = &tempSec[0][0];

If you want to treat a 3×3 array as an int*, you should probably declare it as an int[9], and use tempSec[3*x+y] instead of tempSec[x][y].

Alternatively, perhaps what you wanted was int (*pTemp)[3] = tempSec? That would then be a pointer to the first element of tempSec, that first element itself being an array.

You can in fact take a pointer to a 2D array:

int (*pTemp)[3][3] = &tempSex;

You’d then use it like this:

(*pTemp)[1][2] = 12;

That’s almost certainly not what you want, but in your comment you did ask for it…