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Home/ Questions/Q 1028439
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T12:23:17+00:00 2026-05-16T12:23:17+00:00

I have a bash function (slightly simplified for explaining) copy_to() { cp $1 $2

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I have a bash function (slightly simplified for explaining)

copy_to() {
    cp $1 $2 $3
}

This works fine:

copy_to -f /demo/example1.xml new_demo/

But Let’s say I want to copy all the xml files, the following code will have issues:

copy_to -f /demo/*.xml new_demo/

Obviously I could just write cp -f /demo/*.xml new_demo/, but is there anyway to get the copy_to function to work for a list of files (which passes more than just 3 parameters) as well as a single file?

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  1. Editorial Team
    Editorial Team
    2026-05-16T12:23:18+00:00Added an answer on May 16, 2026 at 12:23 pm

    There are $@ and $* which contain a list of all parameters. You should use $@, because it works inside of double quotes. Else, file names containing spaces would break your code.

    copy_to() {
        cp "$@"
    }
    

    If one of the parameters is special, you can use the shift command to remove it from the list of parameters, like so:

    example() {
        destination="$1"
        shift
        echo "copying $@ to $destination"
    }
    

    shift removes the first parameter from the list, therefore you’ll have to save it in another location first. After calling shift, the contents of $1 will be what was $2, $2 will contain what was $3 and so on. $@ expands to all parameters (excluding those that were removed by shift).

    Note that you cannot shift parameters off the end of your parameter list, only from the beginning.

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