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Asked: 2026-06-11T20:58:35+00:00

I have a bash script called foo with variable number of arguments, with the

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I have a bash script called foo with variable number of arguments, with the first one being a required one, i.e.:

foo a1 b2 b3 b4 ...

I understand that in bash $1 will get me argument a1, but is there a way to get all the rest of the arguments? $@ or $* seem to get me all the arguments including a1.

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1 Answer

  1. Editorial Team

    Slice the $@ array.

    echo "${@:2}"
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