Question

I have a basic code here:

<?        
include("inc_dblib.php");
include("inc_ecs.php");
$db = dbconnect();
$id = 10;
?>
<?php echo text_view($db,$id,"<h3><br />^lead^</h1>   <br />^text^");?>
    <br />

inside inc_ecs.php i have:

function text_view($dblink,$id,$code) {

if( !$rset = dbquery($dblink,"article_view",$id) )
return FALSE;
$item = mysql_fetch_assoc($rset);
$text=$item["text"];
$title=$item["title"];
$lead=$item["lead"];
$capelo=$item["capelo"];
$author=$item["author"];

$vowels = array("^text^","^title^","^capelo^","^lead^", "^author^");                                                        
$yummy = array($text, $title, $capelo, $lead,$author);      
$code = str_replace($vowels,$yummy,$code);
return $code;
}   

however every time I run my script it tells me

Fatal error: Call to undefined function text_view

. Any ideas? Thanks.

Ok
so I found an other problem.
I have tried to insert the echo “Hello World!”; in the code of the inc_ecs.php.
When I browsed the page, I realised that a major part the code it is shown as text.
I turned back to the remote version and it shows a blank page when called in a browser.
the inc_ecs.php page start showning the code from “return $outputVar;” and the remaining hole code of the page is shown:

function graphical_counter ($db, $id){
    $str = counter($db, $id);
    $visitors_split = chunk_split ($str,1,'');
    $visitors = strlen($str);        
    for ($i ; $i< $visitors ; $i++){
        $outputVar .= "<img src='./images/counter/".$visitors_split[$i].".gif' width='15' height='20' border='0' align='absmiddle'>";
    }
    return $outputVar;
}
/*
End Counter Functions

Is there an error in this code ?

Answer 1

your include(); should be inside of the tag:

<?php
include("inc_ecs.php");
echo text_view($db,$id,"<h3><br />^lead^</h1>   <br />^text^");
?>