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Home/ Questions/Q 6963737
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:49:59+00:00 2026-05-27T15:49:59+00:00

I have a batch file as follows; CD C:\MyFolder findstr /c:stringToCheck fileToCheck.bat IF NOT

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I have a batch file as follows;

CD C:\MyFolder
findstr /c:"stringToCheck" fileToCheck.bat
IF NOT XCOPY "C:\OtherFolder\fileToCheck.bat" "C:\MyFolder" /s /y

I am getting an error (“C:\OtherFolder\fileToCheck.bat” was unexpected at this time.) when trying to execute this.

Please let me know what I am doing wrong.

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:50:00+00:00Added an answer on May 27, 2026 at 3:50 pm

    You are not evaluating a condition for the IF. I am guessing you want to not copy if you find stringToCheck in fileToCheck. You need to do something like (code untested but you get the idea):

    CD C:\MyFolder
    findstr /c:"stringToCheck" fileToCheck.bat
    IF NOT ERRORLEVEL 0 XCOPY "C:\OtherFolder\fileToCheck.bat" "C:\MyFolder" /s /y
    

    EDIT by dbenham
    The above test is WRONG, it always evaluates to FALSE.
    The correct test is IF ERRORLEVEL 1 XCOPY ...

    Update: I can’t test the code, but I am not sure what return value findstr actually returns if it doesn’t find anything. You might have to do something like:

    CD C:\MyFolder
    findstr /c:"stringToCheck" fileToCheck.bat > tempfindoutput.txt
    set /p FINDOUTPUT= < tempfindoutput.txt
    IF "%FINDOUTPUT%"=="" XCOPY "C:\OtherFolder\fileToCheck.bat" "C:\MyFolder" /s /y
    del tempfindoutput.txt
    
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