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Home/ Questions/Q 3351472
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:54:46+00:00 2026-05-18T01:54:46+00:00

I have a big problem with a java program. I try to implement a

  • 0

I have a big problem with a java program.
I try to implement a simple software.
There is a label and i wanna stamp a text in this label but this must be separate by 2 sec.

I have seen a problem with the thread and Swing and I implemented this code but the result not change.
Can you help me please
Thanks

 public void stampChips1(int numberDecrement){

        ActionListener taskPerformer = new ActionListener() {
            public void actionPerformed(ActionEvent evt) {
                jLabel1.setText("L'avversario ha deciso di togliere : . ");
            }
        };
        new javax.swing.Timer(2000, taskPerformer).start();


        ActionListener taskPerformer2 = new ActionListener() {
            public void actionPerformed(ActionEvent evt) {
                jLabel1.setText("L'avversario ha deciso di togliere : . . ");
            }
        };
        new javax.swing.Timer(2000, taskPerformer2).start();


        ActionListener taskPerformer3 = new ActionListener() {
            public void actionPerformed(ActionEvent evt) {
                jLabel1.setText("L'avversario ha deciso di togliere : . . .");
            }
        };
        new javax.swing.Timer(2000, taskPerformer3).start();



        jLabel1.setText("L'avversario ha deciso di togliere : " + numberDecrement);
    }
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  1. Editorial Team
    Editorial Team
    2026-05-18T01:54:47+00:00Added an answer on May 18, 2026 at 1:54 am

    Every time you call javax.swing.Timer.start() in your code, it will continue to fire events every 2 seconds (as set in your constructors). After a few intervals, you eventually have three different timers trying (and succeeding) to set the text in the same label. The text of the label will depend on which Timer’s ActionListener has last finished executing. If you want a Timer to fire once and stop you should set it up like this:

    javax.swing.Timer tmr = new javax.swing.Timer(2000, taskPerformer);
    tmr.setRepeats(false);
    tmr.start();
    

    Now each timer will fire once only, eliminating any overwriting issues on the label.

    Added per request in comments:

    When you set up each timer, set it up to only fire once (and as camickr stated), set each timer with a different interval.

    The first timer should be:

    javax.swing.Timer tmr1 = new javax.swing.Timer(2000, taskPerformer);
    tmr1.setRepeats(false);
    tmr1.start();
    

    The second timer should be similar: tmr2 = new ... (4000, taskPerformer2);
    The third timer should be similar: tmr3 = new ... (6000, taskPerformer3);

    The problem with your initial code is that when your stampChips1(int) method executes it first sets up three Timers to fire events EVERY two seconds, and then writes to the label.

    time
    0s – jLabel1 = “L’avversario ha deciso di togliere : ” + numberDecrement
    ~2s – jLabel1 = “L’avversario ha deciso di togliere : . “
    ~2s – jlabel1 = “L’avversario ha deciso di togliere : . . “
    ~2s – jlabel1 = “L’avversario ha deciso di togliere : . . .”
    ~4s – jLabel1 = “L’avversario ha deciso di togliere : . “
    ~4s – jlabel1 = “L’avversario ha deciso di togliere : . . “
    ~4s – jlabel1 = “L’avversario ha deciso di togliere : . . .”

    All of your timers are firing close to the same time, and they won’t stop until you call Timer.stop() or tell it to fire only once with Timer.setRepeats(false).

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