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Home/ Questions/Q 736365
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:35:46+00:00 2026-05-14T07:35:46+00:00

I have a bit of a special requirement when combining lists. I will try

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I have a bit of a special requirement when combining lists. I will try to illustrate with an example. Lets say I’m working with 2 lists of GamePlayer objects. GamePlayer has a property called LastGamePlayed. A unique GamePlayer is identified through the GamePlayer.ID property. Now I’d like to combine listA and listB into one list, and if a given player is present in both lists I’d like to keep the value from listA.

I can’t just combine the lists and use a comparer because my uniqueness is based on ID, and if my comparer checks ID I will not have control over whether it picks the element of listA or listB. I need something like:

for each player in listB
{
    if not listA.Contains(player) 
    {
        listFinal.Add(player)
    }
}

However, is there a more optimal way to do this instead of searching listA for each element in listB?

****EDIT****: Alternately, what if I wanted to choose which GamePlayer I keep based on the value of LastGamePlayed (instead of knowing that ListA takes precedence over ListB)? So I want a unique list of GamePlayer objects but for each player I want the GamePlayer object with the most recent LastGamePlayed? Basically I need a way to determine which object to keep when there are duplicate GamePlayers.

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:35:46+00:00Added an answer on May 14, 2026 at 7:35 am

    Now that this has been clarified, the question is basically this:

    • Combine all elements from list A and list B, and if there are any duplicates, keep the one with the newest LastGamePlayed.

    I would do this with a grouping:

    var players = from p in listA.Concat(listB)
                  group p by p.ID into g
                  select g.OrderByDescending(x => x.LastGamePlayed).First();
    

    If performance is an issue, there are “faster” ways to write this, but I would start with this.

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