Question

I have a block of code in $(function() { function parseData(){...} )};

I also have a function declared outside of the ready block. This is outside since I hook it up in codebehind ie ddlCategories.Attributes.Add("onchange", "getDataFields()");

From the getDataFields function, I need to call parseData but it does not seem to find it.

How do I access my parseData() which is in my ready block, from outside of the ready block?

(sorry if some of terminology is off – I am now to JS)

Answer 1

Any reason parseData() has to be in the ready block? Why not just make it a top level function:

<script type="text/javascript">

function parseData() { ... }

$(document).ready( function() {
   ddl.Categories.....
}
<script>