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Home/ Questions/Q 166257
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Asked: May 11, 20262026-05-11T12:03:58+00:00 2026-05-11T12:03:58+00:00

I have a block of code like this that runs as a child thread:

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I have a block of code like this that runs as a child thread:

if(someVar == 1){ doSomeStuff;  _exit(0) } else    execvp(*(temp->_arguments), temp->_arguments); printf('I'm done\n'); 

When I run the program with someVar == 1, I understand that the _exit(0) call kills my thread. However, when it’s set to 0, why doesn’t the program continue after the execvp() call and do the printf statement?

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  1. 2026-05-11T12:03:59+00:00Added an answer on May 11, 2026 at 12:03 pm

    If you exec* (call any exec function from the exec family), then the code of a new program is loaded into your current process and execution continues with its main function and its stuff. On a successful execution of those functions, they will never return because your printf does not exist anymore in memory.

    I think you confuse exec* with the fork function. That will splice off a new child process which will run the same code as the parent.

    If what you want is to create a new thread, that shares data and the address space with the main thread, you should use the pthread_create function. A new process will not share data and you will have to communicate with the other process using other mechanisms, like pipes or shared memory.

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  • added an answer Try this. May 11, 2026 at 3:58 pm
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