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Editorial Team
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Asked: 2026-06-17T23:17:42+00:00

I have a <body style=<?php include(gallery.php); ?> where gallery.php holds a random array of

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I have a <body style="<?php include("gallery.php"); ?>" where gallery.php holds a random array of images, echoing the URL upon each reload.

I would like to have a button to refresh the background image of the body.

I currently am able to do one reload of the image, since the new URL is echoed.

EG:

$(".refresh").click(function() {
    $("body").css("background-image", "url(<?php include("gallery.php"); ?>)");
});

But after the inclusion of the gallery file in the script, it is always the same url.

EDIT
My PHP is as follows:

$bg = array(
    array( "url" => "url_1" ),
    array( "url" => "url_2" ),
    ...
);


for ($i=0;$i<1;$i++) {
    $id = array_rand($bg);
    echo "{$bg[$id]['url']}";
    unset($ad[$id]);
};
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1 Answer

  1. Editorial Team

    It would be in an another way and gallery.php could outputs an image (not just a url), So you can access gallery.php like this :

    $(".refresh").click(function() { 
    $("body").css("background-image", 'url("http://www.mysite.com/gallery.php?'+Math.random()+'")'); 
});

    Using Math.random() will passes a random number to avoid caching.

    So in gallery.php you have something like :

    $bg = array(
    array( "url" => "url_1" ),
    array( "url" => "url_2" ),
    ...
);

shuffle($bg); // Random order

echo file_get_contents($bg[0]['url']);
//instead of echo $url;
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