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Home/ Questions/Q 4594664
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T22:51:36+00:00 2026-05-21T22:51:36+00:00

I have a bunch of code that looks like this: with tempfile.NamedTemporaryFile() as tmpfile:

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I have a bunch of code that looks like this:

with tempfile.NamedTemporaryFile() as tmpfile:
    tmpfile.write(fileobj.read()) # fileobj is some file-like object
    tmpfile.flush()
    try:
        self.sftp.put(tmpfile.name, path)
    except IOError:
        # error handling removed for ease of reading
        pass

Is it possible to do an upload like this without having to write the file out somewhere?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T22:51:37+00:00Added an answer on May 21, 2026 at 10:51 pm

    Update As of Paramiko 1.10, you can use putfo:

    self.sftp.putfo(fileobj, path)
    

    Instead of using paramiko.SFTPClient.put, you can use paramiko.SFTPClient.open, which opens a file-like object. You can write to that. Something like this:

    f = self.sftp.open(path, 'wb')
    f.write(fileobj.read())
    f.close()
    

    Note that it may be worthwhile to feed paramiko data in 32 KiB chunks, since that’s the largest chunk underlying SSH protocol can handle without breaking it into multiple packets.

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