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Home/ Questions/Q 6802171
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:11:27+00:00 2026-05-26T19:11:27+00:00

I have a bunch of modules that export an IModule interface. So in the

  • 0

I have a bunch of modules that export an IModule interface. So in the main program I have no problems

...
let mutable modules = Seq.empty
[<ImportMany>]
member x.Modules
    with get():IEnumerable<Lazy<IModule, IModuleData>> = modules
    and set(a) = modules <- a
...

But now I need to expose an interface back to those modules. So each module will import a single interface

...
let mutable parent:IParent = ?
[<Import>]
member x.Parent
    with get():IParent = parent
    and set(a) = parent <- a
...

So my problem is how do I go about creating my mutable “parent” when I have no initial value for it? Also, is this the appropriate way to expose an API back to component parts?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:11:27+00:00Added an answer on May 26, 2026 at 7:11 pm
    let mutable parent = Unchecked.defaultof<IParent>
    

    should do the trick.

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