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Asked: 2026-05-14T22:02:11+00:00

I have a bunch of Users . Since Django doesn’t really let me extend

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I have a bunch of Users. Since Django doesn’t really let me extend the default User model, they each have Profiles. The Profiles have a referred_by field (a FK to User). I’m trying to get a list of Users with >= 1 referral. Here’s what I’ve got so far

Profile.objects.filter(referred_by__isnull=False).values_list('referred_by', flat=True)

Which gives me a list of IDs of the users who have referrals… but I need it to be distinct, and I want the User object, not their ID.

Or better yet, it would be nice if it could return the number of referrals a user has.

Any ideas?

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1 Answer

  1. Editorial Team

    Took me a long time to wrap my head around this, but I think I finally got it figured out:

    affiliates = User.objects.annotate(num_referrals=Count('referrals')).filter(num_referrals__gt=0)

    I didn’t think I’d be able to use the reverse relationship 

     referred_by = models.ForeignKey(User, null=True, blank=True, related_name='referrals')

    in Count(), nor did I think you could use the annotated value in the filter… that’s pretty cool. I still wish you could use GROUP BY without having to annotate stuff (assuming I didn’t need the count).

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