Question

I have a C application called Test. Test takes in a single int parameter. I want to run Test with many different parameters, so I made the following bash script:

#!/bin/bash
for i in {0..5}
do
    ./Test "$i" 
done

However, this executes ./Test "$i" and not ./Test 0, ./Test 1 etc. Changing it to ./Test $i simply executes ./Test $i 5 times.What am I doing wrong?

Answer 1

Try

#!/bin/bash
for i in `seq 0 5`
do
    ./Test $i 
done

To create sequences in bash you can use seq, which has an advantage of working in any bourne-compatible shell (that is, seq works everywhere because it’s an external program, it’s the for loop that becomes more portable).

Yes, it makes no difference with respect to ./Test invocation, but it provides a respectful reason to procrastinate before fixing ./Test.