Question

I have a C++ class called Foo. If I follow the Cython C++ tutorial I will need to call the Python class differently, PyFoo for example.
However I really need to call the Python class Foo as well. How to do that efficiently?

Edit: I’m trying to interface an existing C++ library that was previously interfaced with Boost Python. For different reasons I would like to test Cython instead.
Since with Boost:Python Python classes were called with the same name as in C++, I would like to continue with this naming convention. It’s not a Python (CPython) requirement to call classes differently, but it seems to be imposed by Cython, at least in the tutorial.

I can of course use a pure python module to define a Foo class that calls PyFoo, but this seems both boring and inefficient.

Answer 1

There are two ways to handle this.

1. Declare C++ class with an alternate name; original name has to be specified in double quotes:

   cdef extern from "defs.h" namespace "myns":
       cdef cppclass CMyClass "myns::MyClass":
           ...
   

   Then you can use MyClass for your python class and refer to C++ declaration as CMyClass.

   Note that original name has to include the namespace explicitly (if it is namespaced).
   Cython template arguments (when present) should go after an alternate name declaration.

2. Declare your C++ classes in a separate .pxd file, named differently from your .pyx file, then import them with cimport.

   In cpp_defs.pxd:

   cdef extern from "defs.h" namespace "myns":
       cdef cppclass MyClass:
           ...
   

   In py_wrapper.pyx:

   cimport cpp_defs as cpp
   
   cdef class MyClass:
       cpp.MyClass *_obj