Question

i have a c++ class like the below one working at vc++ , but doesnt work anymore in linux gcc 4.7. And i have no idea how to make it work again.

test.h

template<typename a>
class test: public a
{
public:
    void fun();
};

test.cpp

template<typename a>
void test<a>::fun()
{
   template_class_method(); <-- this is a public method from template_class 
}
    template class test<template_class>;

template_class.h

class template_class {
public:
    template_class();
    virtual ~template_class();
    void template_class_method();

};

template_class.cpp

#include "templateclass.h"

template_class::template_class() {
    // TODO Auto-generated constructor stub

}

template_class::~template_class() {
    // TODO Auto-generated destructor stub
}

void template_class::template_class_method() {
}

Answer 1

You need to qualify it with the base class name as:

a::template_class_method();

The qualification a:: is necessary because template_class_method exists in a. The C++ rule is that if the base is a class template or template argument, then all its members are not automatically visible to the derived classes. In order to help the compiler to find the member, you need to tell it to look for the member in the base class, for which you need to qualify the member which is of the form of base::member_function() or base::member_data.

In your case, since the base is a, and the member is template_class_method, so you have to write this:

a::template_class_method();

Note that such a base class is called dependent base class since it depends on the template argument.