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Home/ Questions/Q 9284351
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T18:52:45+00:00 2026-06-18T18:52:45+00:00

I have a C function declared as follows: void getIndexOfState(long *p, long C, long

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I have a C function declared as follows:

void getIndexOfState(long *p, long C, long G, long B, long *state);

Nowadays my cython wrapper code uses the buffer syntax from numpy array:

cpdef int getIndexOfState(self, np.ndarray[np.int_t, ndim=1, mode="c"] s):
    cdef long out
    getIndexOfState(&out, self.C, self.G, self.B, <long*> s.data)
    return out

I want to use the new memoryview syntax, my question is, how can I pass the pointer to the data when using a memoryview?

I tried:

cpdef int getIndexOfState(self, long[:] s):
    cdef long out
    getIndexOfState(&out, self.C, self.G, self.B, s)
    return out

which raised the “Cannot assign type ‘long[:]’ to ‘long *'” error when I was trying to compile the module. There is any way to pass that pointer without coercing the memoryview back to a numpy array before calling the C function?

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  1. Editorial Team
    Editorial Team
    2026-06-18T18:52:47+00:00Added an answer on June 18, 2026 at 6:52 pm

    If the underlying data is properly contiguous/strided and there is at least one element in the memory, then it should suffice to pass a pointer to the first element (and maybe the length):

    getIndexOfState(&out, self.C, self.G, self.B, &s[0])
    

    EDIT:

    One way to ensure “properly contiguous” should be the addition of “[::1]”.

    cpdef int getIndexOfState(self, long[::1] s):
        cdef long out
        getIndexOfState(&out, self.C, self.G, self.B, &s[0])
        return out
    
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