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Asked: May 10, 20262026-05-10T22:13:20+00:00 2026-05-10T22:13:20+00:00

I have a C# method that projects the value of a number from an

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I have a C# method that projects the value of a number from an interval to a target interval.
For example: we have an interval of -1000 and 9000 and a value of 5000; if we want to project this value to an interval of 0..100 we get 60.

Here is the method:

/// <summary>   /// Projects a value to an interval /// </summary> /// <param name='val'>The value that needs to be projected</param>   /// <param name='min'>The minimum of the interval the value comes from</param>   /// <param name='max'>The maximum of the interval the value comes from</param>   /// <param name='intervalTop'>The minimum of the interval the value will  /// be projected to</param>   /// <param name='intervalBottom'>The maximum of the interval the value will  /// be projected to</param>   /// <returns>Projected value</returns>  public decimal ProjectValueToInterval(decimal val,                                         decimal min,                                         decimal max,                                         decimal intervalBottom,                                        decimal intervalTop)   {       decimal newMin = Math.Min(0, min);     decimal valueIntervalSize = Math.Abs(max - newMin);     decimal targetIntervalSize = Math.Abs(intervalTop - intervalBottom);      decimal projectionUnit = targetIntervalSize / valueIntervalSize;      return (val * projectionUnit) + Math.Abs((newMin * projectionUnit)); } 

This method needs to be called for thousands of values.
I was wondering if there is a more efficient way to do this in C#? If yes, what changes do you suggest?

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  1. 2026-05-10T22:13:20+00:00Added an answer on May 10, 2026 at 10:13 pm

    Just maths. What you’re ‘projecting’ is a normalisation of ranges A-B and A’-B’ such that:

    ratio r = (x-A) / (B-A) = (y-A’) / (B’-A’)

    which using your terms is:

    (val-min) / (max-min) = (returnValue-intervalBottom) / (intervalTop-intervalBottom)

    which solves for returnValue as:

    returnValue =  ((intervalTop-intervalBottom) * (val-min) / (max-min)) + intervalBottom 
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