Question

I have a c# .net app. So I created a notifyIcon that sits in the tray. What I want to do is when the user hits the “x” button on the form, I want it to close to the tray. They should only be able to exit program by using the context menu in the tray icon.

So what I did was, on the form close event, I check whether the form is visible. If its visible, i set it to invisible and set showInTaskbar to false (simulating minimize to tray) If the form is invisible already, then they are probably closing it from the tray, so I will exit the program in that case.

However, the problem I have is that if the window is visible, but they right click on the context menu of the tray icon and hit exit, I need to exit the program and not minimize.

How do I solve this problem?

Answer 1

try this:

bool _closingFromMenu;

void NOTIFYICON_EXIT_MENU_HANDLER(object sender, EventArgs e)
{
    _closingFromMenu = true;
    Close();
}

//form closing handler
FormClosing +=(a,b) =>{
    if(_closingFromMenu){
        Close();
    }
    else{
        e.Cancel = true;
        //do minimize stuff;
    }
}

or if you have only one form you can call Application.Exit(); in context menu item handler