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Home/ Questions/Q 7588637
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:58:18+00:00 2026-05-30T19:58:18+00:00

I have a C++ project that is using QT4. I’ve used QT Designer to

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I have a C++ project that is using QT4. I’ve used QT Designer to build my form, and in the top bar I have "File -> Open Image". The “Open Image” piece is designated by the QT Designer as a QObject with objectName: actionOpen_Image.

How do I go from a user pressing this QObject, to selecting an image and getting its path so I can load it?

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:58:19+00:00Added an answer on May 30, 2026 at 7:58 pm

    Generally, menu items are QAction objects – if you can get your object to be an action, that would be a good first step.

    QActions have a signal triggered which is emitted when selected by a user. This signal can be connected to a slot which can be part of an existing QObject or custom-defined.

    To create and object with a slot, the following example may be helpful:

    class MyClass : QObject{
    Q_OBJECT //<---macro which flags the class for the Meta-Object Compiler(moc) tool
    public:
      MyClass(QObject* parent=):QObject(parent){}
    public slots: //<--- also for the moc tool to handle
      void mySlot(){
        //custom behavior
        QString fileName = QFileDialog::getOpenFileName(/*args*/);
      }
    };
    

    Here, the QFileDialog class is used (via a static method) to get the name of a file. You can set filters for file types and other useful properties, and the dialog will use the native file-dialog of whatever operating system you’re working with.

    Use the connect(QObject* sender, SIGNAL, QObject* receiver, SLOT) method to connect the QAction::triggered signal to the slot you wish to be activated.

    Actual implementation is up to you of course, hope this can get you started.

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