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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:36:18+00:00 2026-05-14T14:36:18+00:00

I have a C# system using 160 bit numbers, stored in a BigInteger. I

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I have a C# system using 160 bit numbers, stored in a BigInteger. I want to display these things on a circle, which means mapping the 0->2^160 range into the 0->2Pi range. How would I do this?

The approach that jumps instantly to mind is

BigInteger number;
angle = (number / pow(2, 160)) * TwoPi;

However, that has complexities because the division will truncate the result into an integer.

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:36:18+00:00Added an answer on May 14, 2026 at 2:36 pm

    Ok, again, from the start.

    Since your BigInteger is from 0 -> 2^160 it’s smaller than a double, which can contain from 10^(-308) to 10^(+308).

    There is an explicit conversion from BigInteger to double.

    So you do this:

    BigInteger number;
    var angle = ((double)number / Math.Pow(2, 160)) * TwoPi;
    

    I do know that you’ll lose precision, but that shouldn’t matter on the circle.

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