Question

I have a call to

long long a = sqrt(n/2);

Both a and n are long long‘s but it won’t let me compile because it says my use of sqrt() is an ambiguous call. I don’t see how it’s possibly ambiguous here at all. How do I resolve this? I have the same problem with floor().

My includes

#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;

Answer 1

There are several overloads of sqrt() and floor(), there’s no “best match” for a call to sqrt(long long) according to the overload resolution rules. Just cast the argument to the appropriate type — i.e.,

long long a = sqrt(static_cast<double>(n/2));