Question

I have a CCNode with a certain rotation. For the sake of simplicity lets say its rotated 45 degrees, size is 100*100 and position is 200,200.

I’m looking to find the 4 corner coordinates (marked as green) on this image. Is there any method in the framework that I can use for this or do I need to do it manually with trigonomery? In that case how can I do that the easiest way?

The best thing is if I could make this a method in the CCNode class so its easily accessible.

Answer 1

CCNode.h:

/** Converts a Point to world space coordinates. The result is in Points.
 @since v0.7.1
 */
- (CGPoint)convertToWorldSpace:(CGPoint)nodePoint;

/** Converts a Point to node (local) space coordinates. The result is in Points.
 @since v0.7.1
 */
- (CGPoint)convertToNodeSpace:(CGPoint)worldPoint;

Example:

// top right corner of your node 
CGPoint topRight = ccp(node.contentSize.width, node.contentSize.height);
// same point in world coordinates
CGPoint topRightWorld = [node convertToWorldSpace:topRight];