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Home/ Questions/Q 7727617
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T05:30:13+00:00 2026-06-01T05:30:13+00:00

I have a certain text in Java, and I want to use pattern and

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I have a certain text in Java, and I want to use pattern and matcher to extract something from it. This is my program:

public String getItemsByType(String text, String start, String end) {

    String patternHolder;
    StringBuffer itemLines = new StringBuffer();

    patternHolder = start + ".*" + end;

    Pattern pattern = Pattern.compile(patternHolder);
    Matcher matcher = pattern.matcher(text);

    while (matcher.find()) {
        itemLines.append(text.substring(matcher.start(), matcher.end())
                + "\n");
    }

    return itemLines.toString();
}

This code works fully WHEN the searched text is on the same line, for instance:

String text = "My name is John and I am 18 years Old"; 

getItemsByType(text, "My", "John");

immediately grabs the text “My name is John” out of the text. However, when my text looks like this:

String text = "My name\nis John\nand I'm\n18 years\nold"; 

getItemsByType(text, "My", "John"); 

It doesn’t grab anything, since “My” and “John” are on different lines. How do I solve this?

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  1. Editorial Team
    Editorial Team
    2026-06-01T05:30:14+00:00Added an answer on June 1, 2026 at 5:30 am

    Use this instead:

    Pattern.compile(patternHolder, Pattern.DOTALL);
    

    From the javadoc, the DOTALL flag means:

    Enables dotall mode.

    In dotall mode, the expression . matches any character, including a line terminator. By default this expression does not match line terminators.

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