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Home/ Questions/Q 8659599
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T16:03:06+00:00 2026-06-12T16:03:06+00:00

I have a channel object that contains an array of filterL objects. Each filterL

  • 0

I have a channel object that contains an array of filterL objects. Each filterL object has some data H. Typing the following into the console . . .

channel.filterL(:).H

gives the output . . .

ans =

   0.0140 - 0.0414i
   0.0133 - 0.0181i
   0.0131 - 0.0095i
   0.0131 - 0.0042i
   0.0131 - 0.0000i


ans =

   0.0140 - 0.0416i
   0.0133 - 0.0181i
   0.0131 - 0.0095i
   0.0131 - 0.0042i
   0.0131 - 0.0000i


ans =

   0.0140 - 0.0420i
   0.0133 - 0.0181i
   0.0131 - 0.0095i
   0.0131 - 0.0042i
   0.0131 - 0.0000i

I cannot simply sum this output like so . . .

>> sum(channel.filterL(:).H)
??? Error using ==> sum
Too many input arguments.

So my question is how do I efficiently reorganise my data so that it can be summed?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T16:03:08+00:00Added an answer on June 12, 2026 at 4:03 pm

    Concatenate your data first to change it into one array

    [channel.filterL(:).H]
    
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