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Home/ Questions/Q 8530451
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T09:14:59+00:00 2026-06-11T09:14:59+00:00

I have a CharField type with a choices field as follows: class Thing(models.Model): def

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I have a CharField type with a choices field as follows:

class Thing(models.Model):
    def __unicode__(self):
        return self.name

    A = 'a'
    B = 'b'
    C = 'c'

    TYPE_CHOICES = (
        (A, 'a'),
        (B, 'b'),
        (C, 'c'),
    )
        ...
    type = models.CharField(max_length = 1, choices=TYPE_CHOICES)
        ...

Now when I try to access a page add/thing I am getting a DatabaseError at /path/to/thing/add/
column “type” of relation “place_thing” does not exist

I checked the database (postgres), and I found that type was not a column as said in the error.

Why is the type field not being added when I sync or migrate the database?

How can I create the columns ‘TYPE_CHOICES’ and ‘type’ in my database (postgres)?

Can someone explain to me what would be created by the database for class Thing?

Thank you

katie

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  1. Editorial Team
    Editorial Team
    2026-06-11T09:15:00+00:00Added an answer on June 11, 2026 at 9:15 am

    I ended up using

    ALTER TABLE table_name ADD COLUMN type varchar(30);

    and this worked

    i guess the TYPE_CHOICES column was already made

    thanks

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