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Home/ Questions/Q 6209233
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:56:48+00:00 2026-05-24T05:56:48+00:00

I have a chart where I need to display a different bar for each

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I have a chart where I need to display a different bar for each relevant year that comes up. Prior to running a query, I have no idea what years will be returned and displayed. I need each year bar to have it’s own unique color that is visibly distinguishable from other years. I also need to be able to reproduce the results of the method (for example, 2011 would always return some exact shade of green). Ideally, I would have a simple method that looks like this:

public static Color GetColorFromYear(int year)
{
    // Some magic.
}

I guess there are probably easy ways to convert an integer to a color value, but I’m hoping someone has solved this problem in a way that produces a nice color scheme and distinguishable colors. Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:56:49+00:00Added an answer on May 24, 2026 at 5:56 am

    I would just use a cycle of colors by taking the modulus of the year, for however many colors you want to use:

    public static Color GetColorFromYear(int year)
    {
        var colors = new Color[] { Color.Red, Color.Yellow, Color.Green, ... };
        return colors[year % colors.Length];
    }
    

    If you want to generate some rainbow of colors, you could use a loop sequence with Color.FromArgb to generate a gradient of colors. This can be adapted to different levels of gradients or different color schemes by changing the for loop parameters and the various components of red, green, and blue.

    var colors = new List<Color>();
    
    // red to green
    for (int i = 10; i <= 250; i += 30)
        colors.Add(Color.FromArgb(255 - i, i, 0))
    
    // green to blue
    for (int i = 10; i <= 250; i += 30)
        colors.Add(Color.FromArgb(0, 255 - i, i))
    
    // blue to red
    for (int i = 10; i <= 250; i += 30)
        colors.Add(Color.FromArgb(i, 0, 255 - i))
    
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