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Home/ Questions/Q 9174233
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T16:43:09+00:00 2026-06-17T16:43:09+00:00

I have a child class that starts a method of the base class as

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I have a child class that starts a method of the base class as a thread. The child class has also implemented a pure virtual method from the base class. The thread then needs to call the child’s implemented version of the pure virtual method in the thread, but the thread throws an exception: “Pure virtual method called.” The code below demonstrates what happens on construction of a Child:

class Base {
  std::thread messageThread;

  virtual void processMessage(std::string msg) = 0;

  static void checkForMessages(Base *c) {
    while(true) {
      std::string msg = "Hello";
      c->processMessage(msg);
    }
  }
};

class Child : public Base {
  Child() {
    messageThread = std::thread(checkForMessages, this);
  }

  void processMessage(std::string msg) {
     std::cout << "Message: " << msg << std::endl;
  }
};

My understanding is that Child is still considered a Base until after the constructor finishes, so the thread is only able to see processMessage as a pure virtual function. I could implement checkForMessages for every child of Base, but that defeats the purpose of having the Base class in the first place.

How can I implement this correctly? Thank you for the help!

Edit: A complete example that demonstrates the issue, with an attempted fix: https://gist.github.com/4590476

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  1. Editorial Team
    Editorial Team
    2026-06-17T16:43:10+00:00Added an answer on June 17, 2026 at 4:43 pm

    Nothing stops the instance of Derived from being destroyed (or at least starting to be) before the thread runs. You need some smart pointers or some synchronization.

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