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Home/ Questions/Q 6016573
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:00:07+00:00 2026-05-23T03:00:07+00:00

I have a childwindow with an associated VM that gets created each time I

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I have a childwindow with an associated VM that gets created each time I ask the child window to open. when the childwindow opens, it registers a listener for an MVVM Light message. After I close the window, I’m pretty sure that I’m releasing all references to it, but I don’t actually call dispose because it does not implement IDisposeable.

When I instanciate another child window of the same type, and send it a different context, I know that I’m receiving the message from the previous instanciation of the VM… each time I use the window, more and more VM are listening, and the code repeats.

How can I be sure that my previous VM that registered to listen to a message, has actually been released and is no longer active. Is there a deterministic way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:00:08+00:00Added an answer on May 23, 2026 at 3:00 am

    Whenever you register a message you should make sure that you unregister the message as well. To unregister you can use Cleanup method on classes deriving from ViewModelBase. In other cases, e.g. a view, you should implement a method hat is called when the view is unloaded – e.g by trapping and handling the unloaded event on a control or view. In this method you then call Messenger.Unregister(EventTarget).

    This behaviour is a quirk in the current version of the toolkit, and Laurent is aware of it.

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