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Home/ Questions/Q 288079
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:47:00+00:00 2026-05-12T05:47:00+00:00

I have a ciphertext, encrypted in 3DES CBC mode, and I’m having some trouble

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I have a ciphertext, encrypted in 3DES CBC mode, and I’m having some trouble decrypting it. I have the following information (not actual values):

<?php
// Three 16 character long keys
$key1 = '1234567890123456';
$key2 = '6543210987654321';
$key3 = '6549873210456123';

// The initialisation vector
$ivec = '0102030405060708';

// A token which looks something like this
$token = '2ad82e09e3b4e7c491e4bb9fb7c606e1';
?>

I based my decryption function off the PHP Class that is found in this blog post. It looks like this:

<?php
function decrypt($key,$iv,$token) {
    $td = mcrypt_module_open('tripledes', '', 'cbc', ''); 
    $iv = substr($iv, 0, mcrypt_enc_get_iv_size($td)); 
    $expected_key_size = mcrypt_enc_get_key_size($td); 

    $key = substr(md5($key), 0, $expected_key_size); 
    mcrypt_generic_init($td, $key, $iv);

    $decrypted_string = trim(mdecrypt_generic($td, base64_decode($token)));

    mcrypt_generic_deinit($td); 
    mcrypt_module_close($td); 

    return $decrypted_string;
}
?>

However, I’m not sure how to feed the three keys into the algorithm. I have tried chaining them together like so: $key1.$key2.$key3, and in reverse order, but to no avail.

Any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:47:01+00:00Added an answer on May 12, 2026 at 5:47 am

    // Three 16 character long keys

    $expected_key_size is 24, 3*8. The keys are most likely in hex format.

    function foo($hex) {
        $rv = '';
        foreach(str_split($hex, 2) as $b) {
            $rv .= chr(hexdec($b));
        }
        return $rv;
    }
    
    // Three 16 character long keys
    $key1 = '1234567890123456';
    $key2 = '6543210987654321';
    $key3 = '6549873210456123';
    
    $key = foo($key1.$key2.$key3);
    
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