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Home/ Questions/Q 198667
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:57:26+00:00 2026-05-11T16:57:26+00:00

I have a class (A web control) that has a property of type IEnumerable

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I have a class (A web control) that has a property of type IEnumerable and would like to work with the parameter using LINQ.

Is there any way to cast / convert / invoke via reflection to IEnumerable<T> not knowing the type at compile time?

Method void (IEnumerable source)
{
    var enumerator = source.GetEnumerator();

    if (enumerator.MoveNext())
    {
        var type = enumerator.Current.GetType();
        Method2<type>(source); // this doesn't work! I know!
    }
}

void Method2<T>(IEnumerable<T> source) {}
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  1. Editorial Team
    Editorial Team
    2026-05-11T16:57:26+00:00Added an answer on May 11, 2026 at 4:57 pm

    Does your Method2 really care what type it gets? If not, you could just call Cast<object>():

    void Method (IEnumerable source)
    {
        Method2(source.Cast<object>());
    }
    

    If you definitely need to get the right type, you’ll need to use reflection.

    Something like:

    MethodInfo method = typeof(MyType).GetMethod("Method2");
    MethodInfo generic = method.MakeGenericMethod(type);
    generic.Invoke(this, new object[] {source});
    

    It’s not ideal though… in particular, if source isn’t exactly an IEnumerable<type> then the invocation will fail. For instance, if the first element happens to be a string, but source is a List<object>, you’ll have problems.

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